How to contact me.
Several people have asked me about unsolved problems.
I will take the easy way out: see the list of 50 problems
in
Bondy
and Murty. I hope it will not annoy the authors of that text if
I will reproduce that list here,
and perhaps (eventually) add to it.
Problems number above 50 are from other sources.
Some of these problems have been solved (and thus the title is slightly incorrect) and
I won't claim to be
familiar with all current results.
If you find that one of them has been solved
(or even that some reasonable progress has been made),
please e-mail me. (How to contact me.)
Also, I'm not giving you all of the references in
Bondy
and Murty. You should get yourself a copy of that book.
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By
Haken
and Appel,
every 2-edge-connected planar graph has a
4-colourable orientable cycle double cover.
Similarly, If G can be embedded on an orientable
surface S such that every face boundary
is a cycle, then G has an orientable cycle double cover.
Tarsi (1986) and L. Goddyn (1989) proved that every
2-edge-connected graph with a Hamilton path has a
6-colourable cycle double cover.
Early references to the cycle double conjecture include:
[P. Seymour, 1979] [G. Szekeres, 1973]
For an excellent survey article see:
F. Jaeger. A survey of the cycle double conjecture.
Cycles in Graphs,
Annals of Discrete Mathematics 27(1985), 1-12.
Conjecture 51. Prove that every 2-edge-connected graph has an
orientable 5-colourable cycle double cover.
If a 2-connected graph is (2k-1)-generated, it is obviously
k-path-connected. The connection the other way was not so obvious to me at that time. What appears in the 1992 paper is that if G is ((k-1)2+1)-path-connected, then
G is (k+1)-generated. See
Locke (1992).
Warning, Conjecture 4 of that paper is false (take subdivisions of the dodecahedron).
But Conjecture 5 of that paper is correct:
Question 54. What is the best positive constant m such that
every k-path-connected graph must be
(mk)-generated.
It is obvious that any k-path-connected graph G (other than K1) must have a cycle of length at least k+1 in each block. Thus, G is t-generated for k+3<=2t<=k+4. (HTML doesn't yet have a nice way of saying: t is the least integer bounding half of k+3 from above.)
(H.J. Voss visited me in 2002, after the 33rd CGTC Conference and, having forgotten I had already posted the above note (c. 2000), we generated the proof again.)
Question 55.
Does the sequence c3,c4,...
approach 1?
Question 55(b). Let dk denote a similar parameter
for k-regular, k-connected graphs. Thus,
d3 is between 2/3 and 7/8.
Is the sequence d3,d4,...
non-decreasing and does it approach 1?